A solid disk (mass = 1 kg, R=0.5 m) is rolling across a table with a translational speed of 9 m/s.

a.) What must the angular speed of the disk be?
rad/s

d.) The disk then rolls up a hill of height 2 m, where the ground again levels out. Find the translational and rotational speeds now.
m/s
rad/s

Is translational speed not what I am supposed to use as my "v"? and is angular speed not w= v/r?

1 answer

a) w = V/R = 9/0.5 = 18 rad/s
d) potential energy increases my M g H, so total kinetic energy must decrease by that amount. That is (3/4) m V^2 for a solid disc. Solve for V