A solid cylinder of radius 0.85m is released from rest from a height of 1.8m and rolls down the incline as shown. What is the linear speed of the cylinder when it reaches the horizontal surface?

Answer 1

Total Ke = g m h = (1/2) m v^2 + (1/2) I w^2
where v = w r
so
m g h = (1/2) m v^2 + (1/2) (1/2) m r^2 (v^2/r^2)

2g h = v^2 + v^2/2 = 1.5 v^2
2 (9.81)(1.8) = 1.5 v^2