A solid cylinder,mass 100kg, is suspended in water between two tight cables so that the circular faces are horizontal and the upper face is 0.20m below the surface.The area of a circular cross-section of the cylinder is 0.50m² and it's height is 0.20m . The density of water is 1000kg/m³.

Question

1) Calculate the pressure in excess of that due to the atmosphere at the top and at the base of the cylinder.

Answer 1

The pressure in excess of that due to the atmosphere at the top and base of the cylinder can be calculated using the formula:

pressure = density * gravity * height

1) At the top of the cylinder:
pressure_1 = density_water * gravity * height_1
pressure_1 = 1000 kg/m³ * 9.81 m/s² * 0.20 m
pressure_1 = 1962.00 Pa

2) At the base of the cylinder:
pressure_2 = density_water * gravity * (2*height - height_1)
pressure_2 = 1000 kg/m³ * 9.81 m/s² * (0.40 m - 0.20 m)
pressure_2 = 1962.00 Pa

Therefore, the pressure in excess of that due to the atmosphere at the top and base of the cylinder is 1962.00 Pa.