Asked by Alisha
A solenoid 74.5 cm long has 350 turns and
a radius of 2.26 cm.
If it carries a current of 1.69 A, find the
magnetic field along the axis at its center.
Answer in units of T
a radius of 2.26 cm.
If it carries a current of 1.69 A, find the
magnetic field along the axis at its center.
Answer in units of T
Answers
Answered by
Steve
Magnetic field = permeability x turn density x current
For a solenoid of length L =0.745m with N =350 turns,
the turn density is n=N/L turns/m.
If the current in the solenoid is I =1.69 amperes
and the relative permeability of the core is k =1( air)
then the magnetic field at the center of the solenoid is
1*(350/.745)*1.69 T
For a solenoid of length L =0.745m with N =350 turns,
the turn density is n=N/L turns/m.
If the current in the solenoid is I =1.69 amperes
and the relative permeability of the core is k =1( air)
then the magnetic field at the center of the solenoid is
1*(350/.745)*1.69 T
Answered by
Alisha
It says its wrong
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