A soild cube of aluminum (density2.70g/cm^3) has a volume of 0.200cm^3 . It is known that 27.0g of aluminum contains 6.02x10^23 atoms .
How many aluminum atoms are contained in the cube ?
1 answer
.2 cm^3 * 2.7g/cm^3 * 6.02*10^23atoms/27.0g = 1.204*10^22 atoms
1 answer