a softball batter hits a fly ball that is caught 3.8 seconds later, 88m from home plate. The ball is caught at the same height from which it was thrown.

Question

What was its initial velocity?

What is the maximum height above its launch point that it reached?

Answer 1

the velocity is the vector sum of the horizontal and vertical components

horizontal ... 88 m / 3.8 s

vertical ... time up equals time down
... (3.8 s / 2) * 9.8 m/s^2

the max height is half the initial vertical component, multiplied by half the flight time