A soccer player kicks a 0.43 kg ball straight up to see how far it will rise. The ball starts with a velocity of 16m/s at a height of 0.85m above the ground. It rises then falls straight down to the ground.

Question

a) what is the total energy of the ball just after it is kicked?
b) How high above its original position does the ball rise?
c) What is the velocity of the ball when it hits the ground?

Answer 1

total energy= PE + KE. The question on PE, relative to what point? ground? Assuming ground
total initial energy= mh*.85 + 1/2 m 16^2

b( at the top, KE is zero...Pe = intial energy, so figure h

c. final KE= initial total energy, solve for v.

Answer 2

Bull