A soccer player is kicking a .8 kg soccer ball at rest and creates a force of 70 Newtons and accelerates the ball to a velocity of 15 meters per second. What is the magnitude of the impulse of the player throwing the ball?

Answer 1

To find the magnitude of the impulse, we need to use the impulse-momentum theorem, which states that the impulse (J) is equal to the change in momentum (ΔP) of an object. The formula for impulse-momentum theorem is as follows:

J = ΔP = mv - mu

Where:
J = impulse
ΔP = change in momentum
m = mass
v = final velocity
u = initial velocity (which is 0 m/s since the ball is at rest)

Given:
m = 0.8 kg (mass of the soccer ball)
v = 15 m/s (final velocity of the soccer ball)
u = 0 m/s (initial velocity of the soccer ball)

J = mv - mu
J = (0.8 kg) * (15 m/s - 0 m/s)
J = (0.8 kg) * (15 m/s)
J = 12 kg·m/s

Therefore, the magnitude of the impulse of the player kicking the ball is 12 Newton-seconds or 12 kg·m/s.