the initial downward speed is 25/2 ft/s
so, how long does it take to hit the ground?
h(t) = 50-12.5t-16t^2 = 0
now, using that t value, recall that
v(t) = -12.5 - 32t
the horizontal speed is constant, at 25*0.866 ft/s
a soccer ball is kicked from the top of a 50ft high hill with an initial velocity of 25ft/s at angle 30 degrees below horizontal. At what velocity will it strike the ground? b. How long would it take the ball to reach the ground c. What is the range that the kicked ball will cover?
1 answer