A soccer ball is kicked from the ground with initial speed 17 m/s. at angle(a 20 Find a) The horizontal distance that the ball travels after 4s? b) The speed of the ball at the highest point?

Answer 1

I guess you mean 20 degrees above horizontal.

u = horizontal velocity, does not change
= 17 cos 20
so
a) (17 cos 20)4

b) u = 17 cos 20
At the highest point, there is no vertical velocity, so the answer is u = 17 cos 20

Answer 2

Vi = 17 sin 20 = 5.81
t = 5.81/9.81 =.593 seconds upward
so in the air 2*.593 = 1.19 seconds in the air
so it is not in the air for five seconds
and the answer to part a is
d = u t = 17 * cos 20 * 1.19
= 19 meters