s. velocity=acceleration*time
= (1.82@200)*5=91@200
Now, for position
position=origposit+vi*t+1/2 a t^2
= compute each individually, then convert to x,y coordinates, then add x,y separately.
A snowmobile is originally at the point with position vector 31.5 m at 95.0° counterclockwise from the x axis, moving with velocity 4.29 m/s at 40.0°. It moves with constant acceleration 1.82 m/s2 at 200°. After 5.00 s have elapsed, find the following.
(a) its velocity vector
(b) its position vector
1 answer