(x,y) at start:
x = 28.7 cos 95 = 28.7 * -0.0872 = -2.50
y = 28.7 sin 95 = +28.6
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velocity at t = 0
Vix = 4.13 cos 40 = 3.16
Viy = 4.13 sin 40 = 2.65
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ax = 2.05 cos 200 = -1.93
ay = 2.05 sin 200 = -0.701
velocity at t = 5
Vx = 3.16 -1.93 (5)= -6.49m/s
Vy = 2.65 -0.701(5) = -0.855 m/s
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X = -2.50 + 3.16 * 5 - (1/2)(1.93)(25)
Y = 28.6 +2.65*5 - (1/2)(0.701)(25)
A snowmobile is originally at the point with position vector 28.7 m at 95.0° counterclockwise from the x axis, moving with velocity 4.13 m/s at 40.0°. It moves with constant acceleration 2.05 m/s2 at 200°. After 5.00 s have elapsed, find the following.
(a) its velocity vector
v =
(b) its position vector
r =
1 answer