You don't need to solve for other velociites. Calculate the time T that it takes to hit the ground. That time is T = 44.4 m/(15 m/s)
Get the height H from the vertical motion relationship.
(1/2) g T^2 = H
Note that V does not enter since there was no initial vertical velocity component.
A snowball is launched horizontally from the top of a building at v = 15 m/s. If it lands d = 44.5 meters from the bottom, how high (in m) was the building?
For this problem, do I need to solve for any other velocities? I'm a little stuck...I'm not quite sure how to solve problems given only velocity and distance yet.
1 answer