Question

A snack bar sells two sizes of snack packs. A large snack pack is $5 and a small pack is $3. In one day, the snack bar sold 60 packs for a total of $220. Write a system of equations that represents the scenario above. Let x = small packs and y = large snack packs. How many small packs did the snack bar sell? Use the elimination method to solve. (SOLVE FOR X)

Answer 1

The system of equations can be written as:

x = number of small packs
y = number of large packs

1) x + y = 60 (total number of packs sold)
2) 3x + 5y = 220 (total cost of packs sold)

To solve using the elimination method, we'll multiply equation 1 by 3:

3x + 3y = 180
3x + 5y = 220

Subtract equation 1 from equation 2:

(3x + 5y) - (3x + 3y) = 220 - 180
2y = 40

Divide both sides by 2:

2y/2 = 40/2
y = 20

Thus, the snack bar sold 20 large packs.