A small sphere of mass m = 7.50 g and charge

Question

q1 = 32.0 nC is attached to the end of a string and hangs vertically as shown in
the figure. A second charge of equal mass and charge q2 = –58.0 nC is located a
distance d = 2.00 cm below the first charge.
(a) Find the tension in the string.
(b) If the string can withstand a maximum tension of 0.180 N, what is the
smallest value d can have before the string breaks?

Answer 1

(a) T= m1•g + F(el)= m1•g+ k•q1•q2/r²=
=7.5•10⁻³•9.8 + 9•10⁹•32•10⁻⁹•58•10⁻⁹/0.02²=…
(b) T1= m1•g + F(el)= m1•g+ k•q1•q2/r1²=
T1=0.18 N. Solve for r1

Answer 2

Please i need question and answers

Answer 3

A charged particle A exerts a force of 2.62 N to the right on charged particle B when the particles are
13.7 mm apart. Particle B moves straight away from A to make the distance between them 17.7 mm.
What vector force does particle B then exert on A?
ans : 1.57 N directed to the left