Asked by Rachel
A small pebble is heated and placed in a foam cup calorimeter containing water at 25 °C. The water reaches a maximum temperature of 27 °C. If the pebble released 532.1 J of heat to the water, what mass (in g) of water was in the calorimeter?
Answers
Answered by
DrBob222
heat lost by pebble + heat gained by water = 0
heat lost by pebble = 532.1 J
heat gained by water = mass H2O x specific heat H2O x (Tfinal-Tinitial)
Set q = heat gaine by water and solve for mass H2O.
heat lost by pebble = 532.1 J
heat gained by water = mass H2O x specific heat H2O x (Tfinal-Tinitial)
Set q = heat gaine by water and solve for mass H2O.
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