A small mailbag is released from a helicopter that is descending steadily at 2.87 m/s.

a)After 5.00 s, what is the speed of the mailbag?

b)How far is it below the helicopter?

1 answer

a. vf=vi+gt

g is downward, as is vi

b. distance= vi*t+1/2 g t^2 again, vi, g are negative.