To solve for the cost of one apple (x) and one orange (y), we have the following system of equations:
- \( 6x + 6y = 7.50 \)
- \( 10x + 5y = 8.75 \)
Let's simplify the first equation by dividing all terms by 6:
\[ x + y = 1.25 \quad \text{(Equation 1)} \]
Now, simplify the second equation by dividing all terms by 5:
\[ 2x + y = 1.75 \quad \text{(Equation 2)} \]
Now we can solve the system of equations. We can substitute Equation 1 into Equation 2. From Equation 1, we can express \(y\) in terms of \(x\):
\[ y = 1.25 - x \]
Now substitute this expression for \(y\) into Equation 2:
\[ 2x + (1.25 - x) = 1.75 \]
Combine like terms:
\[ 2x - x + 1.25 = 1.75 \] \[ x + 1.25 = 1.75 \]
Now, solve for \(x\):
\[ x = 1.75 - 1.25 \] \[ x = 0.50 \]
Thus, the cost of one apple is \($0.50\).
So the answer is:
0.5