a small dog is train to jump straight up a distance of 1.2m. how much kinetic energy does the 7.2-kg dog need to jump this high ( the acceleration due to gravity is 9.8m/s2

Answer 1

V^2 = Vo^2 + 2g*d
Vo^2 = V^2-2g*d
Vo^2 = 0-(-19.6*1.2 = 23.52
Vo = 4.85 m/s.

Ek = 0.5m*Vo^2 = 3.6*(4.85)^2 = 11.76 J.

vo^2

Answer 2

CORRECTION:
Ek = 84.672 J.