A small cylinder rests on a circular turntable that is rotating clockwise at a constant speed. The

Question

cylinder is at a distance of r = 12 cm from the center of the turntable. The coefficient of static
friction between the bottom of the cylinder and the surface of the turntable is 0.45. What is the
period of the cylinder if it is travevling at the maximum speed v
max that the cylinder can have
without slipping off the turntable?

Answer 1

mv²/R =μmg
v=sqrt(μgR) =
=sqrt(0.45•9.8•0.12)=0.73 m/s
T=2πR/v = 2π•0.12/0.73 = 1.03 s.