Using the same pressure and the same tire we know the volume for He is the same as the volume for HBr gas. Use Graham's Law. Let's use a volume of 2 L.
So rate for He is 1 L/2 sec = 0.5 L/s. rate HBr = 1 L/seconds. I've let mm stand for molar mass. Then
(rate He/rate HBr) = sqrt (mm HBr/mm He)
Substitute the numbers and solve. Post your work if you get stuck.
A small bicycle pump is filled with helium (He) gas. With constant
pressure, the gas is forced out through a small aperture in two
seconds. The same pump is filled with hydrogen bromide (HBr) gas.
Using the same pressure, how long will it take to force out this gas?
2 answers
9 second
1 answer