(1) Vo - gt = 40 - 9.8*3 = 10.6 m/s
The direction will still be upwards, since the number is positive.
(2) The height increase H will be such that added potential energy
M*g*H equals initial kinetic energy, (M/2*(Vo^2).
H = Vo^2/(2g) = 81.6 m
(3) Maximum height occurs when V = 0
Vo - gt = 0
t = 4.08 s.
(4)Time going up = Time coming down.
Total time = 2*4.08 = 8.16 s
A small ball is thrown vertically upwards with an initial velocity of 40m/s. Find:(1) its velocity after moving 3 seconds(2) the maximum heigh attained(3) the time to attain the maximum height(4)the total time taken for the ball to return to the ground again
1 answer
1 answer