g = 9.81 m/s^2
v = Vi - g t
at top v = 0
t = 25/9.81 seconds to top
double that for time in air
m g h = (1/2) m Vi^2
h = 625/(2*9.81)
v is 0 at top of course
a is -9.81 m/s^2 forever until it hits the mud.
a slingshot launches a rock straight upward at 25 m/s, how high does the rock go, how long is it in the air, what is the velocity and the acceleration of the rock at its highest point
1 answer