Well, constant speed means no net force, so friction must equal the component of weight down the hill
mg*mu*cosTheta=mg*SinTheta
TanTheta=mu
check my thinking.
A sled slides down a snow-covered hill at CONSTANT SPEED. If the hill makes an ANGLE of 10degrees ABOVE THE HORIZONTAL, WHAT IS THE COEFFICIENT OF KINETIC FRICTION BETWEEN THE SLED AND THE SNOW?
~>HELP!
3 answers
0.176
Coefficient of kinetic friction=
tan0- Accelaration/gcos0
tan0- Accelaration/gcos0