A sled slides down a snow-covered hill at CONSTANT SPEED. If the hill makes an ANGLE of 10degrees ABOVE THE HORIZONTAL, WHAT IS THE COEFFICIENT OF KINETIC FRICTION BETWEEN THE SLED AND THE SNOW?

Question

A sled slides down a snow-covered hill at CONSTANT SPEED.  If the hill makes an ANGLE of 10degrees ABOVE THE HORIZONTAL, WHAT IS THE COEFFICIENT OF KINETIC FRICTION BETWEEN THE SLED AND THE SNOW?

~>HELP!

bobpursley · Answer

Well, constant speed means no net force, so friction must equal the component of weight down the hill mg*mu*cosTheta=mg*SinTheta TanTheta=mu check my thinking.

Karl · Answer

0.176

Karl · Answer

Coefficient of kinetic friction= tan0- Accelaration/gcos0