A skip in a mine shaft weights 10kN and carries a load of 15 kN.the shaft is 300m deep and the cable weights 60N/m. Determine the work done if the cage is lifted from the 300m level to the 200m level

Answer 1

First, we need to calculate the total weight being lifted by the cable:
Total weight = weight of the skip + weight of the load
Total weight = 10 kN + 15 kN
Total weight = 25 kN

Next, we calculate the weight of the cable itself:
Weight of the cable = (300m - 200m) * 60N/m
Weight of the cable = 100m * 60N/m
Weight of the cable = 6000N = 6kN

Therefore, the total weight being lifted by the cable is:
25 kN + 6 kN = 31 kN

Now, we calculate the work done using the formula:
Work = force * distance
Work = 31 kN * 100 m
Work = 3100 kN.m

Therefore, the work done to lift the cage from the 300m level to the 200m level is 3100 kN.m.