sin25.4 = h/53, h = 53*sin25.4 = 22.7 m.
PE = M*g*h = 60*9.8*22.7 = 13,367 J.
KE = PE, 0.5M*V^2 = 13,367, 30*V^2 = 13367, V = 21.1 m/s. = Velocity at bottom of slope.
A skier with a mass of 60.0 kg starts from rest and skis down an icy (frictionless) slope that has a length of 53.0 m at an angle of 25.4° with respect to the horizontal. At the bottom of the slope, the path levels out and becomes horizontal, the snow becomes less icy, and the skier begins to slow down, coming to rest in a distance of 137 m along the horizontal path. What is the speed of the skier at the bottom of the slope?
1 answer
0 answers