A skier wants to build a rope tow to pull herself up a ski hill that is inclined at 15 with the horizontal. Calculate the tension needed in the rope to give the skier's 54kg body a 1.2 m/s^2 acceleration.

Answer 1

see other post.

Answer 2

M*g = 54 * 9.8 = 529.2 N. = Wt. of skier.

Fp = 529.2*sin15 = 137 N. = Force parallel to the hill.

Fn = 529.2*Cos15 = 511 N. = Normal force.

Fap-Fp = M*a.
Fap-137 = 54*1.2,
Fap = 201.8 N. = Applied force = Tension in rope.

Answer 3

tuleg