Vo = 26.2 m/s[23o].
Yo = 26.2*sin23 = 10.2 m/s.
a. Y^2 = Yo^2 + 2g*h = 0.
10.2^2 - 19.6h = 0, 19.6h = 104.8, h = 5.3 m.
d*sin23 = 5.3, d = 13.7 m. up hill.
A skier traveling at 26.2 m/s encounters a 23 degree slope.
(a)If you could ignore friction, to the nearest meter, how far up the hill does he go?
(b)If the coefficient of kinetic friction in the previous problem was actually 0.11 and the slope 30 degrees, to the nearest meter how far up the hill does he go?
1 answer