A skier slides down a hill starting with zero velocity at a height of h1 = 45.2 m above the bottom of the hill. The shape of the terrain is like a cosine wave.

Question

a) What is the velocity of the skier on top of the second, intermediate hill, whose height is h2 = 36.5 m? Neglect all frictional effects.

b) What is the skier's velocity at the bottom of the hill?

Answer 1

(1/2) m v^2 = m g h
or
v = sqrt(2 g h)

where h is how far down you moved

g is about 9.81 m/s^2