Ws = mg = 71 kg * 9.81 N./kg = 696 N. =
Weight of skier.
Fs = 696 N. @ 37 Deg. = Force of skier.
Fp = 696*sin37 = 419 N. = Force parallel to slope.
Ff = 0 = Force of friction.
Fn = Fap - Fp - Ff = 0. a = o.
Fap-419-0 = 0,
Fap = 419 N. = Force applied.
h = 62.2*sin37 = 37.4 m.
W = Fap*h = 419 * 37.4 = 15,684 Joules
A skier of mass 71.0 kg is pulled up a slope
by a motor-driven cable.
How much work is required to pull the skier
62.2 m up a 37.0� slope (assumed to be fric-
tionless) at a constant speed of 2.0 m/s? The
acceleration of gravity is 9.81 m/s2 .
1 answer
1 answer