1.Fs = mg*sin A = 583.1*sin1o=10.18 N.
2. Fn = mg*cos1o = 583.1*cos1o=583.0 N.
A skier of mass 59.5 kg comes down a slope of constant angle 1◦ with the horizontal.
The acceleration of gravity is 9.8 m/s^2
i. What is the force on the skier parallel to the slope?
Answer in units of N.
ii. What force normal to the slope is exerted by the skis?
Answer in units of N.
1 answer
1 answer