PE at top: m g h
Ke at the bottom equals PE at top.
1/2 m v^2=mgh
v=sqrt(2gh)
a skier, mass 61 kg is at the top of a hill and starts down with an initial speed of 5m/s. he does no work on the way down, assume that the hill surface is frictionless. find his speed at the bottom of the hill which is 10m below the top.
2 answers
so 14m/s?