Please start with a free-body diagram, then resolve forces parallel and normal to the slope.
See
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Assuming the skier (the round object) is moving up the slope, then the friction force is towards downslope.
The towbar force is therefore, equating forces along the slope,
F=mg sin(θ)+μ(mg cos(θ))
substitute
m=55.3 kg
g=9.81 m/s^2
θ=23°
μ=0.110
I get a little less than 270 N.
A skier is pulled up a slope at a constant velocity by a tow bar. The slope is inclined at 23.0° with respect to the horizontal. The force applied to the skier by the tow bar is parallel to the slope. The skier's mass is 55.3 kg, and the coefficient of kinetic friction between the skis and the snow is 0.110. Calculate the magnitude of the force that the tow bar exerts on the skier.
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