A skier is gliding along at 6.93 m/s on horizontal, frictionless snow. He suddenly starts down a 17.2° incline. His speed at the bottom is 29.7 m/s. What is the length of the incline?

Question

i understand that the equation used is gH= change in (v^2)/2

so i plug in
9.8H=(29.7^2-6.93^2)/2

9.8H=396.5
H=396.5/9.8
H=40.45 m

but this answer still comes up as wrong? can anyone help me with where i'm going wrong?

Answer 1

YOu found the vertical drop on the incline. The distance is quite something else, along the incline

H=dSin17.2
solve for d, given H above. I didn't check your math.

Answer 2

so thatd be H=dSin17.2

40.45m=dsin17.2
d=40.45/sin17.2
d=136.8

it all looks right, but for some reason incorrect, if anyone has a chance, can you check my math for me? i cant understand where i went wrong