a skaterboarder is moving 5.25 m/s when he starts to roll up a frictionless hill. how much higher is he when he comes to a stop? (energy problem)

Answer 1

all the KE (1/2 mv^2) is converted to PE (mgh) So,

1/2 mv^2 = mgh
v^2 = 2gh
h = v^2/2g