A skateboarder, with an initial speed of 3.2 m/s , rolls virtually friction free down a straight incline of length 16 m in 3.3 s. At what angle θ is the incline oriented above the horizontal?

Answer 1

s = 3.2t + 1/2 at^2
3.2(3.3) - a/2 (3.3^2) = 16
a = 1.0

so, a = 1/9.8 g
So, sin(theta) = 1/9.8
theta = 5.86 degrees