Pr(even)=2/3
pr(odd)=1/3
a. Pr(all five even)=(2/3)^5
b. I dont understand...2 or 3 trials will give (how many) even numbers?
A six faced is so constructed that the probability of getting an even number is twice the probability of getting an odd number. Find the probabilities that out of 5 trials
(1)all the five will give even numbers
(3)2 or 3 trails will give even numbers ....find by binomial distribution method...
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Yes I got it my answer thank you ...bobpursley
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