The velocity of the satellite in terms of G and the mass of Earth, mp, can be calculated using the formula for the orbital velocity:
v = √(G * mp / r)
where r is the orbital radius.
Plugging in the values:
v = √(G * mp / 3.9×10^3)
Therefore, the correct answer is (3.9×103)Gmp−−−−√
a sitealite is orbiting Earth at an orbital radius of 3.9×103 m. What is its velocity in terms of G and the mass of Earth, mp? (Ignore units in the answer.)(1 point)
Responses
(2.6×10−4)Gmp−−−−√
(6.2×101)Gmp−−−−√
(1.6×10−2)Gmp−−−−√
(3.9×103)Gmp−−−−√
3 answers
Let G be the universal gravitational constant and mp be the mass of the planet a satellite is orbiting. Which equation could be used to find the velocity of the satellite if it is placed in a geostationary orbit?(1 point)
Responses
v=Gmp(15,522 km)−−−−−−−−√
v=Gmp(48,115 km)−−−−−−−−√
v=Gmp(7,324 km)−−−−−−−√
v=Gmp(42,164 km)−−−−−−−−√
Responses
v=Gmp(15,522 km)−−−−−−−−√
v=Gmp(48,115 km)−−−−−−−−√
v=Gmp(7,324 km)−−−−−−−√
v=Gmp(42,164 km)−−−−−−−−√
To find the velocity of a satellite in a geostationary orbit, we can use the equation:
v = √(G * mp / r)
where r is the radius of the orbit.
In a geostationary orbit, the satellite remains fixed above a specific point on the Earth's surface. The radius of this orbit is equal to the radius of the Earth itself. The value is approximately 6,371 km (or 6,371,000 m).
Therefore, the correct equation would be:
v = √(G * mp / 6,371,000)
Hence, none of the given options are correct.
v = √(G * mp / r)
where r is the radius of the orbit.
In a geostationary orbit, the satellite remains fixed above a specific point on the Earth's surface. The radius of this orbit is equal to the radius of the Earth itself. The value is approximately 6,371 km (or 6,371,000 m).
Therefore, the correct equation would be:
v = √(G * mp / 6,371,000)
Hence, none of the given options are correct.