A sinusoidal transverse wave of amplitude ym = 3.2 cm and wavelength = 3.4 cm travels on a stretched cord. Find the ratio of the maximum particle speed (the speed with which a single particle in the cord moves transverse to the wave) to the wave speed.

Answer 1

let L = wavelength, A = amplitude and w = angular frequency

max particle velocity = w A
wave speed = 2 pi w L

ratio (part speed)/(wave speed)
= A/(2 pi L)

Note that the ratio is independent of wave speed, w and cord tension. It would have been necessary to know these parameters to compute either speed.

Answer 2

Can you please relook at the question , the answer I get using the equation you provided did not work .Thank you anyway

A sinusoidal transverse wave of amplitude ym = 3.2 cm and wavelength = 3.4 cm travels on a stretched cord. Find the ratio of the maximum particle speed (the speed with which a single particle in the cord moves transverse to the wave) to the wave speed.
The answer I got is 0.14979288 ( using A/(2 pi L) )

Answer 3

frequency*wavelength=wavespeed
w/2PI * L= wL/2PI

check that.

Answer 4

Thanks Bob. I put the 2 pi in the wrong place.

Answer 5

Thanks alot guys :)