A singly charged positive ion has a mass of 2.74 10-26 kg. After being accelerated through a potential difference of 268 V, the ion enters a magnetic field of 0.450 T, in a direction perpendicular to the field. Calculate the radius of the ion's path in the field.

Question

A singly charged positive ion has a mass of 2.74  10-26 kg. After being accelerated through a potential difference of 268 V, the ion enters a magnetic field of 0.450 T, in a direction perpendicular to the field. Calculate the radius of the ion's path in the field. 
  cm

Anonymous · Answer

mv²/2 =eU v=sqrt(2eU/m)=… mv²/R=evB R= mv/eB=…