Asked by Anonymous
A singly charged ion of unknown mass moves in a circle of radius 13.5 cm in a magnetic field of 2.9 T. The ion was accelerated through a potential difference of 3.0 kV before it entered the magnetic field. What is the mass of the ion? (hint: EPE=Vq=KE)
kg
kg
Answers
Answered by
bobpursley
Vq=1/2 m v^2
v= sqrt 2 Vq/m
centripetal force=magneticforce
1/2 m v^2/r= Bqv
solve for mass.
solve for m.
v= sqrt 2 Vq/m
centripetal force=magneticforce
1/2 m v^2/r= Bqv
solve for mass.
solve for m.
Answered by
Anonymous
what is little v and Q
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