There are 3 odd numbers (1, 3, and 5) and 3 even numbers (2, 4, and 6) on a die.
The probability of getting an odd number on the first roll is 3/6 = 1/2.
After the first roll, there are still 6 equally likely outcomes, but now only 3 even numbers left. So, the probability of getting an even number on the second roll is 3/6 = 1/2.
To find the probability of both events occurring (getting first an odd number and second an even number), we multiply the probabilities: (1/2) * (1/2) = 1/4.
Therefore, the probability of getting first an odd number and second an even number is 1/4.
A single die is rolled twice. The 36 equally-likely outcomes are shown to the right.
Find the probability of getting first an odd number and second an even number
1 answer
1 answer