Mean = 17/10 = 1.7
(1.7 -1.96 * .56 /sqrt(10)), 1.7 +1.96 * .56 /sqrt(10))
A simple random sample of 10 households, the number of TV's that each household had is as follows:
1, 3, 1, 2, 0, 2, 1, 1, 1, 5
Assume that it is reasonable to believe that the population is approximately normal and the population standard deviation is 0.56. What is the lower bound of the 95% confidence interval for the mean number of TV's?
1 answer
3 answers