the KE at the bottom equals the initial PE (mgh) 0f the bob.
1/2 mv^2=mg(1.70cos45)
solve for v. then V^2/r
tension= mg+mv^2/r
A simple pendulum consists of a light string 1.70 m long with a small 0.490 kg mass attached. The pendulum starts out at 45º below the horizontal and is given an initial downward speed of 1.50 m/s.
find:
At the bottom of the arc, determine the centripetal acceleration of the bob.
At the bottom of the arc, determine the tension in the string.
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