A simple open U-tube contains mercury. When 11.9 cm of water is poured into the right arm of the tube, how high above its initial level does the mercury rise in the left arm? Take the density of mercury to be 13.6 g/cm3 and the density of water to be 1.00 g/cm3.

Answer 1

[ (0.5)*11.9 ]/ 13.6= 0.428 cm

Take half of what is added (since it must rise one side and fall is height on the other)- in this case 11.9/2

Divide that by the density of mercury.

Don't ask me why that's right. It just is. #Physics/Chemistry.

Lol.