A simple lever is used to lift a heavy load. When a 60-N force pushes one end of the lever down 1.2 m, the load rises 0.2 m. Show that the weight of the load is 360 N.

Answer 1

Work done by force = work done by load (W)

60 N * 1.2 m = 0.2 m * W

Solve for W to get
W=60*1.2/0.2 N
= 360 N

Answer 2

60N x 1.2m =0.2 x the weight of the load.
As 60 x 1.2/0.2=360N
shown

Answer 3

Astouding

Answer 4

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Answer 5

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Answer 6

60N *1.2M=0.2-0*M