a simple gear system consisting of a gearwheel A and pinion B of which the centre distance is approximately 700 mm. If the circular pitch of the gears is 40 mm and the gears have a velocity ratio of 4:1, calculate: 5.1 The number of teeth on pinion B.

Answer 1

To calculate the number of teeth on pinion B, we first need to determine the number of teeth on gearwheel A.

Given that the velocity ratio is 4:1, it means that the gearwheel A has 4 times more teeth than pinion B.

Let x be the number of teeth on gearwheel A and y be the number of teeth on pinion B.

x = 4y

Next, we can calculate the pitch diameter of gearwheel A:

Pitch diameter of gearwheel A = Number of teeth on gearwheel A * Circular pitch
= x * 40 mm
= 4y * 40 mm
= 160y mm

Since the center distance is approximately 700 mm, we can express this as:

Pitch diameter of gearwheel A + Pitch diameter of pinion B = Center distance
160y + (40y) = 700
200y = 700
y = 3.5

Therefore, the number of teeth on pinion B is 3.5. However, since the number of teeth must be a whole number, we can round this up to the nearest whole number which is 4.

Therefore, the number of teeth on pinion B is 4.