A side of the triangle below has been extended to form an exterior angle of 136°. Find the value of x.

Answer 1

To find the value of x, we need to use the fact that the sum of an exterior angle and its corresponding interior angle is 180°.

Let x be the measure of the interior angle of the triangle.

Since the exterior angle has a measure of 136°, the corresponding interior angle has a measure of 180° - 136° = 44°.

Since the exterior angle and the corresponding interior angle have the extended side as a common side, the other two interior angles of the triangle must add up to 180° - 44° = 136°.

Therefore, the two interior angles opposite the extended side must each have a measure of 136°/2 = 68°.

Since the sum of the three interior angles of a triangle is 180°, we can write the equation:

x + 44° + 68° = 180°

Combining like terms, we have:

x + 112° = 180°

Subtracting 112° from both sides, we find:

x = 180° - 112° = 68°.

Therefore, the value of x is 68°.

Answer 2

thats not right bot

Answer 3

Apologies for the mistake. Let's approach the problem again.

In a triangle, each interior angle and its corresponding exterior angle add up to 180°. Since the exterior angle formed is 136°, the corresponding interior angle is 180° - 136° = 44°.

Let's call one of the interior angles of the triangle x°.

Since the sum of the interior angles of a triangle is 180°, the other two interior angles can be expressed as (180° - x°) and (44°).

To find x°, we add up the three interior angles and set it equal to 180°:

x° + (180° - x°) + 44° = 180°

Simplifying the equation, we get:

224° - x° = 180°

Rearranging the equation, we find:

x° = 224° - 180°

x° = 44°

Therefore, the value of x is 44°.