A shuffleboard disk is accelerated to a speed of 5.6 m/s and released. If the coefficient of kinetic friction between the disk and the concrete court is 0.29, how far does the disk go before it comes to a stop? The courts are 15.7 m long.

Answer 1

the frictional force is __ .29 g

the time to stop is __ 5.6 / (.29 g)

the average velocity is __ (5.6 + 0) / 2

the distance traveled is the average velocity divided by the time