the height is
y = 2.2 + 14*sin(36)t - 4.9t^2
solve for t when y=0
The horizontal speed is a constant 14*cos(36), so now you can see how far it traveled.
A shot-putter throws the shot ( mass = 7.3 kg) with an initial speed of 14.0 m/s at a 36.0 ∘ angle to the horizontal.
Calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20 m above the ground.
1 answer
1 answer